`**` on `ZZxxZZ` defined by `(a,b)**(c,d)=(a-c,b-d)` for all `(a,b),(c,d)inZZxxZZ.`

Let A=NxxN , and let * be a binary operation on A defined by (a , b)*(c , d)=(a d+b c , b d) for all (a , b), (c , d) in NxxNdot Show that: * is commutative on Adot (ii) * is associative on Adot

Let A=N uu{0}xx N uu{0} and let * be a binary operation on A defined by (a,b)*(c,d)=(a+c,b+d) for all (a,b),(c,d)in A. Show that * is commutative on A.

Let A=N uu{0}xx N uu{0} and let * be a binary operation on A defined by (a,b)*(c,d)=(a+c,b+d) for all (a,b),(c,d)in A* show that * is associative on A.

Let A=NxxN , and let * be a binary operation on A defined by (a ,\ b)*(c ,\ d)=(a d+b c ,\ b d) for all (a ,\ b),\ (c ,\ d) in NxxNdot Show that: * is commutative on Adot (ii) * is associative on Adot

Let A=NxxN , and let * be a binary operation on A defined by (a ,\ b)*(c ,\ d)=(a d+b c ,\ b d) for all (a ,\ b),\ (c ,\ d) in NxxNdot Show that A has no identity element.

Let A=NxN , and let * be a binary operation on A defined by (a , b)*(c , d)=(a d+b c , b d) for all (a , b),c , d) in NxNdot Show that : '*' is commutative on A '*^(prime) is associative on A A has no identity element.

Let A=NxN , and let * be a binary operation on A defined by (a , b)*(c , d)=(a d+b c , b d) for all (a , b),c , d) in NxNdot Show that : '*' is commutative on A '*^(prime) is associative onA A has no identity element.

Let A=Nuu{0}xxNuu{0} and let * be a binary operation on A defined by (a ,\ b) * (c ,\ d)=(a+c ,\ b+d) for all (a ,\ b),\ (c ,\ d) in Adot Show that * is commutative on Adot

Let A=Nuu{0}xxNuu{0} and let * be a binary operation on A defined by (a ,\ b)*(c ,\ d)=(a+c ,\ b+d) for all (a ,\ b),\ (c ,\ d) in Adot Show that * is associative on Adot

Let S=NNxxNNand** is a binary operation on S defined by (a,b)**(c,d)=(a+c,b+d) for all a,b,c,d in NN . Prove that ** is a commutative and associative binary operation on S.