A radioactive element `A` decays with a decay constant `lambda`. The fraction of nuclei that decayed at any time `t`, if the initial nucle are `N_(0)` is given by:

The decay constant lambda of a radioactive sample:

The decay constant (lambda) for radioactive decay is independent of

The decay constant (lambda) for radioactive decay is independent of

The decay constant lambda of the radioactive sample is probaility of decay of an atom in unit time, then

Nuclei of radioactive element A are produced at rate t^(2) (where t is time) at any time t . The element A has decay constant lambda . Let N be the number of nuclei of element A at any time t . At time t=t_(0), dN//dt is minimum. The number of nuclei of element A at time t=t_(0) is

Nuclei of radioactive element A are produced at rate 't^(2') (where t is time) at any time t . The element A has decay constant lambda . Let N be the number of nuclei of element A at any time t . At time t=t_(0), dN//dt is minimum. The number of nuclei of element A at time t=t_(0) is

The fraction of atoms of radioactive element that decays in 6 days is 7/8. the fraction that decays in 10 days will be

The fraction of atoms of radioactive element that decays in 6 days is (7)/(8) . The fraction that decays in 10 days will be

Nuclei of radioactive element A are being produced at a constant rate. alpha . The element has a decay constant lambda . At time t=0 , there are N_(0) nuclei of the element. Calculate the number N of nuclei of A at time t.