Find the value of `(sin (alpha + beta))/(sin (alpha - beta)), "given that" tan alpha = 2 tan beta.`

Show that (sin (alpha + beta))/( sin (alpha + beta)) = 2, given that tan alpha = 2 tan beta.

(sin (alpha + beta)) / (sin (alpha-beta)) = (a + b) / (ab) rArr (tan alpha) / (tan beta) =

Find the value of sin (alpha - beta), cos (alpha -beta) and tan (alpha - beta), given sin alpha = (8)/(17) , tan beta = (5)/(12), alpha and beta in Quadrant I.

Find the value of sin (alpha + beta) , cos (alpha + beta) , and tan (alpha + beta), given sin alpha = (3)/(5) , cos beta = (5)/(13), alpha and beta in Quadrant I.

If alpha and beta are acute angles and sin alpha = (3)/(5) , sin beta = (8)/( 17), find the values of sin ( alpha + beta), cos (alpha pm beta), and tan ( alpha pm beta).

(sin(alpha+beta))/(sin(alpha-beta))=(a+b)/(a-b) then (tan alpha)/(tan beta)=

sin alpha sin beta-cos alpha cos beta=1 then show that tan alpha+tan beta=0

If sin(alpha + beta) = 4/5 and sin (alpha - beta)= 5/13 , find the value of tan 2 alpha .