`(sinalpha+sinbeta-sin(alpha+beta))/(sinalpha+sinbeta+sin(alpha+beta))=tan(alpha/2)tan(beta/2)`

If 3sinbeta=sin(2alpha+beta) then

If 3sinbeta=sin(2alpha+beta) then

sinalpha+sinbeta=a ,cosalpha+cosbeta=b=>sin(alpha+beta)

sin alpha=sinbeta, cos alpha=cos beta then

(without alpha + without beta-sin (alpha + beta)) / (without alpha + without beta + sin (alpha + beta)) = tan ((alpha) / (2)) tan ((beta) / (2))

Show that: sin^2 alpha + sin^2 beta + 2sinalpha sinbeta cos(alpha+beta)=sin^2 (alpha+beta)

Show that: sin^2 alpha + sin^2 beta + 2sinalpha sinbeta cos(alpha+beta)=sin^2 (alpha+beta)

If alpha,beta in (-pi/2,0) such that (sin alpha+sinbeta)+(sinalpha)/(sinbeta)=0 and (sinalpha+sinbeta) (sinalpha)/(sinbeta)=-1 and lambda=lim_(n->oo) (1+(2sinalpha)^(2n))/((2sinbeta)^(2n)) then :

Find the sum of the series sinalpha+sin(alpha+beta)+sin(alpha+2beta)+sin(alpha+3beta)+.....+sin(alpha+(n-1)beta)

If sinalpha+sinbeta=a ,cosalpha+cosbeta=b=>sin(alpha+beta) =