If `f(n)=|(n!, (n+1)!, (n+2)!),((n+1)!, (n+2)!, (n+3)!), ((n+2)!, (n+3)!, (n+4)!)|` Then the value of 1/1020[(f(100))/(f(99))]` is

Let f(x)=(x-1)(x-2)(x-3)...(x-n),n in N, and f(n)=5040 Then the value of n is

If f(n + 1) = (2f(n) + 1)/2 , n = 1,2,3,....... and f(1) = 2, then find the value of f(101)

If f(n+1)=(2f(n)+1)/(2),n=1,2,3,... and f(1)=2 then find the value of f(101).

If f(1)=1, f(n+1)=2f(n)+1, n ge1 , then f(n) is

Let f(x) = (x - 1)(x - 2)(x - 3)…(x -n), n in N and f(')(n) = 5040 . Then the value of n is …..

If f(1) = 1 and f(n + 1) = 2 f(n) + 1, if n ge 1, then f(n) is.

Let f : N to R be a function satisfying the following conditions: f(1) =1 and f(1) +2f( 2)+ 3 f(3) + ………n f(n )" " f(n ) = n (n+1) , f(n) "for " n ge 2 The value of f(1003) is (1)/(K) . Where K equals

If f(n)=(1)/(n){(n+1)(n+2)(n+3)...(n+n)}^(1//n) then lim_(n to oo)f(n) equals