`sintheta+costheta=sqrt(2)`

If sin theta+costheta=sqrt(2)costheta then what is (costheta-sintheta) equal to ?

Solve the following equations : (vi) sintheta +costheta =sqrt2

Solve: sintheta-costheta=-sqrt2

Solve sqrt3sintheta-costheta=sqrt2

For ____value of theta , sintheta+costheta=sqrt2

sintheta+costheta=(sqrt(3)+1)/(2)

Find the general values of theta from the following equations: sintheta+costheta=(sqrt(3)+1)/(2)

If P={theta:sintheta-costheta=sqrt2costheta} and Q={theta: sintheta+costheta=sqrt2 sintheta} , then show that P = Q.

Let P={theta:sintheta-costheta=sqrt2costheta}and Q={theta: sintheta+costheta=sqrt2sintheta} be two sets. Then