In the given figure, AL || DC, E is mid point of BC. Show that `DeltaEBL ~= DeltaECD`.

In the given figure, the point P bisects AB and DC. Prove that DeltaAPC ~= DeltaBPD (NCERT_TAM_MAT_IX_C07_E01_008_Q01.png" width="80%">

In the figure , in DeltaABC , point D on side BC is such that , DeltaBAC~=DeltaADC then prove that , CA^(2)-=CBxxCD .

In the given figure AB || CD, BC || DE then find the values of x and y

The given figure shows______

In the adjacent figure, we have AC = XD, C and D are mid points of AB and XY respectively. Show that AB = XY.

In the adjacent figure, we have BX = 1/2 AB, BY = 1/2 BC and AB=BC. Show that BX = BY.

In the given Figure AB and CD are intersecting at ‘O’, OA = OB and OD = OC. Show that (i) Delta AOD ~= DeltaBOC and (ii) AD || BC .

In the adjoining figure , seg ML || seg BC , seg NL || seg DC. Prove that AM : AB = AN: AD .

ABC is a right triangle , right angled at A and D is the mid point of AB . Prove that BC^(2) =CD^2 +3BD^(2) .