In `DeltaABC`, the bisector AD of A is perpendicular to side BC Show that AB = AC and `DeltaABC` is isosceles.

The median AD of a DeltaABC is perpendicular to AB, than tanA + 2tanB=

In a quadrilateral ABCD, it is given that AB |\|CD and the diagonals AC and BD are perpendicular to each other. Show that AD.BC >= AB. CD .

In a Delta ABC , AD is the bisector of angle A meeting side BC at D, if AB=10 cm, AC =14 cm and BC=6 cm, find BD and DC.

If AD is the bisector of angle A then AC is

In DeltaABC , P is a point on side BC such that BP = 4 cm and PC = 7 cm. A(DeltaAPC):A(DeltaABC) = ………………

In Delta ABC, AD is the bisector of hat(A). AB = 20 cm, AC = 28 cm, BC = 12 cm Find DC.

In a Delta ABC , AD is the internal bisector of angle A , meeting BC at D . If AB = 5.6 cm, AC = 6cm and DC = 3 cm , find BC

DeltaABC is an isosceles triangle in which AB = AC. Show that /_ B = /_ C.

In DeltaABC, D, E and F are the midpoints of sides AB, BC and CA respectively. Show that DeltaABC is divided into four congruent triangles, when the three midpoints are joined to each other. (ΔDEF is called medial triangle)