AB is a line - segment. P and Q are points on either side of AB such that each of them is equidistant from the points A and B (See Fig ). Show that the line PQ is the perpendicular bisector of AB.

AB is a line segment and line l is its perpendicular bisector. If a point P lies on l, show that P is equidistant from A and B.

If A is (-7,2) and B is (2,-3) then the slope of the line perpendicular to AB is :

Objective : To construct a perpendicular bisector of a line segment using paper folding Procedure : Make a line segment on a paper by folding it and name it as PQ. Fold PQ in such a way that P falls on Q and thereby creating a creas RS. This line RS is the perpendicular bisector of PQ.

Line x + 2y - 8 = 0 is the perpendicular bisector of AB. If B = (3, 5) the A is

Figure shows a square loop of edge a made of a uniform wire. A current i enters the loop at the point A and leaves it at the point C. Find the magnetic field at the point P which is on the perpendicular bisector of AB at a distance a/4 from it.

Let P and Q be point on the line joining A(5,6) and B (3, -4) such that AP=PQ=QB. Then the midpoint of PQ is

Point D and E are the points on sides AB and AC such athat AB = 5.6 , AD = 1.4 , AC =7.2 and AE = 1.8 . Show that DE||BC.

A is a point on either of two lines y+sqrt(3)|x|=2 at a distance of 4/sqrt(3) units from their point of intersection. The coordinates of the foot of perpendicular from A on the bisector of the angle between them are (a) (-2/(sqrt(3)),2) (b) (0,0) (c) (2/(sqrt(3)),2) (d) (0,4)

Objective : To construct a perpendicular to a line segment from as external point using paper folding. Procedure : Draw a line segment AB and mark an external point P. Move B along BA till the fold passes through P and crease it along that line. The crease thus formed is the perpendicular to AB through the external point P.

If A is a point on the Y axis whose rdinate is 8 and B is a point on the X axis whose abscissa is 5 then the equation of the line AB is