D is a point on side BC ΔABC such that AD = AC (see figure). Show that AB > AD.

In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD (see figure) Show that AD = AE

D is a point on side BC of DeltaABC such that , angleADC=angleBAC . Show that AC^(2)= BCxxDC .

In Delta ABC , AB = AC and BC = 6cm, D is a point on the side AC such that AD = 5cm and CD = 4cm, show that Delta BCD ~ Delta ABC and hence find DB .

In the figure, ABC is a triangle in which AB= AC. Points D and E are points on the side AB and AC respectively such that AD=AE. Show that points B, C, E and D lie on a same circle.

In DeltaABC, D is a point on BC such that (BD)/(DC)=(AB)/(AC). prove that AD is the bisector of angleA. (Hint :produce BA to E such that AE=AC. Join EC)

In Delta ABC , with angle B=90^(@) , BC=6 cm and AB=8 cm, D is a point on AC such that AD=2 cm and E is the midpoint of AB. Join D to E and extend it to meet at F. Find BF.

Point D and E are the points on sides AB and AC such athat AB = 5.6 , AD = 1.4 , AC =7.2 and AE = 1.8 . Show that DE||BC.

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is