P is a point in the interior of a parallelogram ABCD. Show that
(i) ar `(DeltaAPB) +ar (DeltaPCD)=1/2ar (ABCD)`
(ii) `ar(DeltaAPD)+ar (DeltaPBC)=ar(DeltaAPB)+ar(DeltaPCD)`
(Hint : Throught , P draw a line parallel to AB)

In the figure ''P'' is a point in the interior of a parallelogram ABCD. Show that area of DeltaAPD+ area of DeltaPBC = area of DeltaAPB+ area of DeltaPCD .

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