Home
Class 9
MATHS
In the figure D, E are points on the si...

In the figure D, E are points on the sides AB and AC respectively of `DeltaABC` such that `ar(DeltaDBC) = ar(DeltaEBC)` . Prove that DE || BC.

Promotional Banner

Topper's Solved these Questions

  • AREAS

    NCERT TAMIL|Exercise EXERCISE 11.2|10 Videos

  • ALGEBRA

    NCERT TAMIL|Exercise Exercise 3.15 (Multiple choice questions)|29 Videos

  • CIRCLES

    NCERT TAMIL|Exercise EXERCISE 12.5|5 Videos

Similar Questions

Explore conceptually related problems

In the figure, ABC is a triangle in which AB= AC. Points D and E are points on the side AB and AC respectively such that AD=AE. Show that points B, C, E and D lie on a same circle.

In Delta ABC , D and E are points on the sides AB and AC respectively. For each of the following cases show that DE||BC (i) AB=12 cm , AD=8 cm, AE=12 cm and AC=18 cm. (ii) AB=5.6 cm, AD=1.4 cm, AC=7.2 cm and AE=1.8 cm.

If D, E and F be the middle points of the sides BC,CA and AB of the DeltaABC , then AD+BE+CF is

In a triangle ABC, if D and E are mid points of sides AB and AC respectively. Show that vecBE+ vecDC=(3)/(2)vecBC .

In the adjacent figure, we have AC = XD, C and D are mid points of AB and XY respectively. Show that AB = XY.

In trapezium ABCD, AB || DC. E and F are points on non-parallel sides AD and BC respectively such that EF || AB. Show that (AE)/(ED) = (BF)/(FC)

If D and E, are the midpoints of the sides AB and AC of a triangle ABC, prove that vec(BE) +vec(DC)=(3)/(2)vec(BC).