In the figure, O is the centre of the circle and AB = CD. OM is perpendicular on `bar(AB)` and `bar(ON)` is perpendicular on `bar(CD)`. Then prove that OM = ON.
Topper's Solved these Questions
CIRCLES
NCERT TAMIL|Exercise EXERCISE 12.1|8 Videos
CIRCLES
NCERT TAMIL|Exercise EXERCISE 12.2|3 Videos
CIRCLES
NCERT TAMIL|Exercise DO THIS|2 Videos
AREAS
NCERT TAMIL|Exercise EXERCISE 11.3|9 Videos
CO-ORDINATE GEOMETRY
NCERT TAMIL|Exercise Try These|2 Videos
Similar Questions
Explore conceptually related problems
In the figure, AB parallel to CD, find x.
In the given figure, AB|| CD. Find the value af x.
In the figure given below, show that length AH gt AB + BC + CD .
In the given figure, AB is one of the diameters of the circle and OC is perpendicular to through the centre O. If AC is 9sqrt(2) cm then what is the area of the circle in cm^(2) .
In the given figure bar(PQ) is a line. Ray bar(OR) is perpendicular to line bar(PQ) . bar(OS) is another ray lying between rays bar(OP) and bar(OR) . Prove that angleROS = (1)/(2) angleQOS − anglePOS