Some points are plotted on a plane such that any three of them are non collinear. Each point is joined with all remaining points by line segments. Find the number of points if the number of line segments are 10.

Find the mid points of the line segment joining the points .

There are 8 points in a plane, no three of them are collinear .The number of triangles that can be formed is:

The end points of a line segment are (2, 3), (4, 5). Find the slope of the line segment.

There are 10 points on a plane of which 5 points are collinear. Also, no three of the remaining 5 points are collinear. Then find (i) the number of straight lines joining these points: (ii) the number of triangles, formed by joining these points.

There are 10 points in a plane and 4 of them are collinear. The number of straight lines joining any two points is

If 10 lines are drawn in a plane such that no two of them are parallel and no three are concurrent , then total number of points of intersection are …………

There are 10 points on a plane of which no three points are collinear. If lines are formed joining these points, find the maximum points of intersection of these lines.

Find the mid point of the line segment joining the points (3, 0) and (-1, 4)