In `Delta ACB, angle C = 90^(@)` and CD`bot` AB
Prove that `(BC^(2))/(AC^(2)) = (BD)/(AD)`.

In angle ACD=90^(@) and CD bot AB . Prove that (BC^(2))/(AC^(2))=(BD)/(AD)

In AD bot BC , prove that AB^(2)+CD^(2)=BD^(2)+AC^(2)

Solve the following sub question in Delta ABD, angle BAD = 90^(@) seg AC bot hypo BD, B - C- D show that (i) AB^(2) = BC : BD (ii) AD^(2) = BD : CD

In Delta ABC, angle B = 90^(@), angle C = 30^(@), AB = 6 cm then AC =….

In the adjacent figure angle BAC=90^(@) and AD bot BC then

In Delta ABC, "seg" AD bot "seg" BC, DB = 3CD . Prove that: 2 AB^(2) = 2AC^(2) + BC^(2)

In the given fig. if AD bot BC Prove that AB^(2) + CD^(2) = BD^(2) + AC^(2) .

ABC is a right triangle , right angled at A and D is the mid point of AB . Prove that BC^(2) =CD^2 +3BD^(2) .

In DeltaABC, angle C = 2 angle A, and AC = 2BC , then the value of (a^(2) + b^(2) c^(2))/(R^(2)) (where R is circumradius of triangle) is ______