`3(1-x) lt 2(x+4)`

Solve: (5 - x)/(3) lt (x)/(2) -4

3x-2 lt 2x+1

A function f [-3, 7] rarr R is defined as follows f(x) = {{: (4x^(2) - 1, " " -3 le x lt 2 ),(3x -2, " " 2 le x le 4 ),(2x -3 , " " 4 lt x lt 7):} Find (i) f (5) + f(6) (ii) f(1) - f(-3) (iii) f(-2)-f(4) (iv) (f(3)+ f(-1))/(2 f(6) - f(1))

Solve log_(3)(x+2)(x+4)+log_(1//3)(x+2) lt 1/2 log_(sqrt3)7 .

If (2x+3)/(5) lt (4x-1)/(2) , then x lies in the interval

If f (x) = {{:(x - 5 ," if ",x le1),(4x^(2)-9," if ",1 ltx lt 2),(3x + 1," if ",x ge 2):} , then the right hand derivative of f(x)at x = 2 is . . . . .

Find all values of x that satisfies the inequality (2x - 3)/((x - 2) (x - 4)) lt 0.

The cumculative distribution function of a discrete random variable is given by F(x)={{:(0, "for "-infty lt x lt 0), ( 1/2, "for " 0 le x lt 1), (3/5, "for " 1 le x lt 2), (4/5, "for " 2 le x lt 3), (9/10, "for " 3 le x lt 4), (1, "for " 4 le x lt infty):} Find (i) the probability mass function (ii) P(X lt 3) and (iii) P(X ge 2) .