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The solution of sec^(2)x tany dx+sec^(2)...

The solution of `sec^(2)x tany dx+sec^(2)y tanx dy=0` is

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The correct Answer is:
`tan x tan y = C`
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NCERT TAMIL-DIFFERENTIAL EQUATIONS-EXERCISE - 9.4
  1. (dy)/(dx) = sqrt(4 - y^(2))(-2 lt y lt 2)

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  2. (dy)/(dx) + y = 1( y ne 1)

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  3. The solution of sec^(2)x tany dx+sec^(2)y tanx dy=0 is

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  4. For each of the differential equations in (e^(x)+e^(-x))dy-(e^(x)-e^...

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  5. (dy)/(dx) = (1 + x^(2))(1 + y^(2))

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  6. Differential equation y log y dx - x dy = 0

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  7. Differential equation x^(5)(dy)/(dx) = - y^(5)

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  8. (dy)/(dx) = sin^(-1)x

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  9. e^(x) tan y dx + (1 - e^(x))sec^(2)y dy = 0

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  10. For the differential equations, find a particular solution satisfying ...

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  11. x(x^(2) - 1)(dy)/(dx) = 1, y = 0 when x = 2.

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  12. cos ((dy)/(dx)) = a (a ne R), y = 2 when x = 0

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  13. (dy)/(dx) = y tan x, y = 1 when x = 0

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  14. Find the equation of a curve passing through the point (0,0) and whose...

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  15. For the differential equation xy(dy)/(dx) = (x + 2)( y + 2), find the ...

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  16. Find the equation of a curve passing through the point (0,-2). Given t...

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  17. At any point (x,y) of a curve, the slope of the tangent is twice the s...

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  18. The volume of spherical balloon being inflated changes at a constant r...

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  19. In a bank, principal increases continuously at the rate of r% per year...

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  20. In a bank, principal increases continuously at the rate of 5% per year...

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