Show that `|veca|vecb+|vecb|veca` is perpendicular to `|veca|vecb-|vecb|veca`, for any two nonzero vectors `vecaandvecb`.

If veca, vecb and vecc are vectors such that |veca|=3,|vecb|=4 and |vecc|=5 and (veca+vecb) is perpendicular to vecc, (vecb+vecc) is perpendicular to veca and (vecc+veca) is perpendicular to vecb then |veca+vecb+vecc|= (A) 4sqrt(3) (B) 5sqrt(2) (C) 2 (D) 12

Show that the vectors 2veca-vecb+3vecc, veca+vecb-2vecc and veca+vecb-3vecc are non-coplanar vectors (where veca, vecb, vecc are non-coplanar vectors).

If |veca|=5|vecb|=4 and |veca+vecb|=1 then |veca-vecb|= ?

If veca and vecb are two vectors, such that veca.vecblt0 and |veca.vecb|=|vecaxxvecb| then the angle between angles between the vectors veca and vecb is

If |veca|=5 , |veca-vecb| = 8 and |veca +vecb|=10 then find |vecb|

given that veca. vecb = veca.vecc, veca xx vecb= veca xx vecc and veca is not a zero vector. Show that vecb=vecc .

Given three vectors e veca, vecb and vecc two of which are non-collinear. Futrther if (veca + vecb) is collinear with vecc, (vecb +vecc) is collinear with veca, |veca|=|vecb|=|vecc|=sqrt2 find the value of veca. vecb + vecb.vecc+vecc.veca

veca and vecb are two vectors such that |veca|=1 ,|vecb|=4 and veca. Vecb =2 . If vecc = (2vecaxx vecb) - 3vecb then find angle between vecb and vecc .

If vectors veca and vecb are non collinear then veca/(|veca|)+vecb/(|vecb|) is