Suppose that 90% of people are right- ha...

Suppose that 90% of people are right- handed. What is the probability that atmost 6 of a random sample of 10 people are right- handed?

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The correct Answer is:

`1-sum_(r=0)^(10) ""^(10)C_(r)(0.9)^(r)(0.1)^(10-r)`

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