Home
Class 11
PHYSICS
A boy standing on a stationary lift ( op...

A boy standing on a stationary lift ( open from above ) throws a ball upwards with the maximum initial speed he can, equal to ` 49 ms^(-1)`. How much time does the ball take to return to his hands ? If the lift starts moving up with a uniform speed of ` 5 ms^(-1)` and the boy again throws the ball up with the maximum speed he can , how hoes the ball take to return to his hands ?

Text Solution

Verified by Experts

10s, 10 s
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    NCERT TAMIL|Exercise EXERCISES|23 Videos

  • MOTION IN A PLANE

    NCERT TAMIL|Exercise EXCERCISES|32 Videos

  • MOTION OF SYSTEM OF PARTICLES AND RIGID BODIES

    NCERT TAMIL|Exercise EXERCISE (V. NUMERICAL PROBLEMS) |6 Videos

Similar Questions

Explore conceptually related problems

A ball of mass 1 kg moving with a speed of 10 ms^(-1) rebounds after a pefect elastic collision with the floor. Calculate the change in linear momentum of the ball.

A ball is dropped from a balloon going up at a speed of 7 m/s. If the balloon was at a height 60 m at the time of dropping the ball, how long will the ball take in reaching the ground?

Knowledge Check

  • If a object is thrown vertically up with the initial speed u from the ground , then the time taken by the object to return back to ground is :

    A
    `(u^(2))/(2g)`
    B
    `(u^(2))/(g)`
    C
    `(u)/(2g)`
    D
    `(2u)/(g)`

  • If a object is thrown vertically up with the initial speed u from the ground , then the time taken by the object to return back to ground is :

    A
    `(u^(2))/(2g)`
    B
    `(u^(2))/(g)`
    C
    `(u)/(2g)`
    D
    `(2u)/(g)`

  • If an object is thrown vertically upward with initial speed 'u'from the ground, then the time taken by the object to return to the ground is

    A
    `(u^(2))/(2g)`
    B
    `(u^(2))/(g)`
    C
    `(u)/(2g)`
    D
    `(2u)/(g)`

    • Similar Questions

    Explore conceptually related problems

    A cricket ball of mass 100 g moving with a speed of 20 ms^(-1) is brought to rest by a player . Find the change in momentum of ball.

    A ball of mass 1 kg moving with a moving with a speed of 10 ms^(-1) rebounds after perfect elastic collision with the floor. Calculate the change in linear momentum of the ball.

    If an object is thrown vertically up with the initial speed w from the ground, then the time taken by the object to return back to ground is

    If an object is thrown vertically up with initial speed u from the ground, then the time taken by the object to return back to ground is

    A cricketer catches a ball of mass 150 gm in 0.1s and which is moving with a speed of 20 ms^(-1) , then he experiences force of…………………….

    Home
    Profile