As shown in Fig. the two sides of a step ladder `BA` and `CA` are `1.6 m` long and hinged at `A`. A rope `DE, 0.5 m` is tied half way up. A weight `40 kg` is suspended from a point `F, 1.2 m` from B along the ladder` BA`. Assuming the floor to be fricionless and neglecting the weight of the ladder, find the tension in the rope and forces exerted by the floor on the ladder. (Take `g = 9.8 m//s^(2))`
(Hint. Consider the eqilibrium of each side of the ladder separately.)

Explanation

Consider the equilibrium of each side of the ladder separately.

Tension = `98 N, N_(B) = 245 N, N_(C) = 147 N`.