Determine the furrent drawn from a 12 V suly with internal resistacne `0.5Omega ` by the infinite network shown in Each rsistor has `1Omega` resistance.

The potential difference between the terminals of a battery of emf 6.0V and internal resistance 1 (Omega) drops to 5.8 V when connected across an external resistor. Find the resistance of the external resistor.

Two batteries one of emf 18 V and internal resistance 2Omega . And the other of emf 12 V and internal resistance 1Omega , are connected as shown. The voltmeter V will velocity record a reading of:

The internal resistance of a 2.1 V cell which gives a current of 0.2A through a resistance of 10 Omega is

The emf of a battey is 3 volts and internal resistance 0.125Omega . The difference of potential at the terminal of battey when connected across an external resistance of 1Omega is

A capacitor of capacitance 100 muF is changed by connecting it to a battery of voltage 12 V with internal resistance 2 Omega . The time after which 99% of the maximum charge is stored on the capactor is

The internal resistance of a 2.1v cell which gives a current of 0.2 A through a resistance of 10 Omega is

A cell of emf E and internal resistance 'r' gives a current of 0.5 A with an external resistance of 12 Omega and a current of 0.25A with an external resistance of 25 Omega . Calculate (i) internal resistance of the cell (ii) emf of the cell.

Shown an arrangement to measure the emf (epsilon) and internal resistance r of a battery. The voltmeter has a very high resistance and the ammeter also has some resistance.The voltmeter reads 1.52 V when the switch S is open.When the switch is closed the voltmeter reading drops to 1.45 V and the ammeter read 1.0A Find the emf and the internal resistance of the battery.