A short bar magnet placed with its axis at `30^@` with a uniform external magnetic field of `0*25T` experiences a torque of magnitude equal to `4*5xx10^-2J`. What is the magnitude of magnetic moment of the magnet?

A short bar magnet placed with its axis at 30^@ with an external field of 0.25 T experiences a torque of magnitude to 4.5xx10^(-2)J . What is the magnitude of magnetic moment of the magnet ?

A short bar magnet placed with its axis at 30^@ to a uniform magnetic field of 0.2 T experiences a torque of 0.060 Nm. i. Calculate magnetic moment of the magnet ii. Find out what orientation of the magnet corresponds to its stable equilibrium in the magnetic field.

A short bar magnet placed with its axis at 30^@ with an external field of 800 G experiences a torque of 0.016 Nm . a. What is the magnetic moment of the magnet ? b. What is the work done in moving it from its most stable to most unstable position ? c. The bar magnet is replaced by a solenoid of cross - sectional area 2xx10^(-4) m^2 and 1000 turns, but of the same magnetic moment . Determine the current flowing through the solenoid.

A short bar magnet o magnetic field . It experiences a torque of 0.05 J. Calculate the magnitude of the magnetic field.

What is the magnetic field along the axis and equatorial line of a bar magnet ?

A bar magnet is placed in a uniform magnetic field whose strength is 0.8 T. Suppose the bar magnet orient an angle 30^(@) with the external field experiences a torque of 0.2 Nm . Calculate : (i) the magnetic moment of the magnet (ii) the work done by an applied force in moving it form most stable configuration to the most unstable configuration and also compute the work done by the applied magnetic field in this case .