If the bar magnet in the above problem is turned around by `180^@`, where will the new null points be located?

If the bar magnet in exercise 13 is turned around by 180^@ where will the new null points be located ?

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north - south direction . Null point are found on the axis of the magnet at 14 cm from the centre of the magnet . The earth's magnetic field at the place if 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null point (i.e., 14 cm) from hte centre of the magnetic ? (At null points , field due to a magnet is equal and opposite to the horizontal component of earth's magnetic field.)

A long bar magnet has a pole strength of 10 Am . Find the magnetic field at a point on the axis of the magnet at a distance of 5cm from the north pole of the magnet.

Consider the situation described in the previous problem. Suppose the current I enters the loop at the point A and leaves it at the point B. Find the magnetic field at the centre of the loop.

A particle of mass m and positive charge q, moving with a uniform velocity v, enters a magnetic field B as shown in (a) Find The radius of the circular arc it describes in the magnetic field. (b) find the angle subtended by the arc at the center. (c ) How long does the particle stay inside the magnetic field? (d) Solve the three parts of the above problem if the charge q on the particle is negative.

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux phi linked with the primary coil is given by phi = phi_0 + 4t , where phi is in weber t is time second and phi_0 is a constant , the output voltage across the secondary coil is:

A projectile is fired at a speed of 100 m/s at an angel of 37^0 above the horizontal. At the highest point, the projectile breaks into two parts of mass ratio 1:3 the smaller coming to rest. Find the distance from the launching point to the where the heavier piece lands.

A bar magnet has length 10 cm and pole strength 50 Am. Calculate the magnetic field at a point distance 20 cm from the centre of the magnet . a. on the axial line b. on the equatorial line

A bar magnet has a length of 8cm. The magnetic field at a point at a distnace 3cm from the centre in the broadside-on position is found to be 4 xx 10^(-6) T . Find the pole strength of the magnet.

The magnetometer of the previous problem is used with the same magent in Tan-B position. Where should the magnet be placed to produce a 37^@ deflection of the needle?