a. Obtain an expression for the mutual inductance between a long straight wire and a square loop of side a as shown in the figure.

b. Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, `v=10m//s`. Calculate the induced emf in the loop at the instant when `x=0.2m`. Take `a=0.1m` and assume that the loop has a large resistance.

Explanation

`M =(mu_0 a)/(2pi) ` In `(1+ a/x)`
`epsi = 1.7 xx 10^(-5) V`