Light from a point source in air falls on a spherical glass surface. If `mu = 1.5`, and radius of curvature `= 20 cm`, the distance of light source from the glass surface is `100 cm` , at what position will the image be formed ? (NCERT Solved Example)

Explanation

We use the relation given by Eq. (9.16). Here

`u=-100cm, v=?, R=+20 cm, n_(1)=1, and n_(2)=1.5`
We then have
`(1.5)/(v)+(1)/(100)=(0.5)/(20)`
`or v=+100cm`
The image is formed at a distance of 100 cm from the glass surface, in the direction of incident light.