What should be the distance between the object and magnifying glass if the virtual image of each square in the figure is to have an area of `6.25 mm^(2)`.Would you be able to see the squares distinctly with your eyes very close to the magnifier ?

Explanation

Magnification `=sqrt((6.25//1))=2.5`
`v=+2.5u`
`+(1)/(2.5u)-(1)/(u)=(1)/(10)`
i.e., `u=-6cm`
`|v|=15cm`
The virtual image is closer than the normal near point (25 cm) and cannot be seen by the eye distinctly.