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The neutron separation energy is defined...

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separation energy of the nuclei `._(20)Ca^(41)` and `._(13)Al^(27)` from the following data : `m(._20Ca^(40))=39.962591u` and `m(._(20)Ca^(41))=40.962278u`
`m(._(13)Al^(26))=25.986895u` and `m(._(13)Al^(27))=26.981541u`

Text Solution

Verified by Experts

Neutron separation energy `S_(n)` of a nucleus `""_(Z)^(A)X` is
`S(n)=[m_(N)(""_(Z)^(A-1)X)+m(n)-m_(N)(""_(Z)^(A)X)]c^(2)`
From given data, `S(n)(""_(20)^(51)Ca)=8.36MeV, S(n)(""_(13)^(27)Al)=13.06MeV`
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