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Under certain circumstances, a nucleus c...

Under certain circumstances, a nucleus can decay by emitting a particle more massive than an `alpha`-particle. Consider the following decay processes:
`._(88)Ra^(223)to._(82)Pb^(209)+._(6)C^(14)`, `._(88)Ra^(223)to._(86)Rn^(219)+._(2)He^(4)`
(a) Calculate the Q-values for these decays and determine that both are energetically allowed.

Text Solution

Verified by Experts

For `""_(6)^(14)C` emission
`Q=[m(N)(""_(88)^(223)Ra)-m(N)(""_(82)^(209)Pb)-m(N)(""_(6)^(14)C)]c^(2)`
`=[m(""_(88)^(223)Ra)-m(""_(82)^(209)Pb)-m(""_(6)^(14)C)]c^(2)=31.85MeV`
For `""_(2)^(4)He" emission, "Q-[m(""_(86)^(223)Ra)-m(""_(86)^(219)Rn)-m(""_(2)^(4)He)]c^(2)=5.98MeV`
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