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Consider the fission .(92)U^(238) by fas...

Consider the fission `._(92)U^(238)` by fast neutrons. In one fission event, no neutrons are emitted and the final stable and products, after the beta decay of the primary fragments are `._(58)Ce^(140)` and `._(44)Ru^(99)`. Calculate Q for this fission process, The relevant atomic and particle masses are:
`m(._(92)U^(238))=238.05079u, m(._(58)Ce^(140))=139.90543 u, m(._(34)Ru^(99))=98.90594 u`

Text Solution

Verified by Experts

`Q=[m(""_(92)^(228)U)+m(n)-m(""_(58)^(140)Ce)-m(""_(44)^(99)Ru)]c^(2)=231.1MeV`
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