` 3 x + 5y = 12, 5x + 3y = 4`.

3 x + 2y = 12 , 5x - 2y = 4 .

1 + 5x + 3y = 9 2x 3y = 12 X = (x, y) - 4

Find the equations of the bisectors of the internal angles of the triangle whose sides are : 3x + 4y -6 = 0, 12x -5y-3 = 0, 4x - 3y + 12 =0 .

{:(3x + 5y = 12),(3x - 5y = - 18):}

Minimise Z = 3x + 5y such that x + 3y ge 3, x + y ge 12, x , y ge 0

If 2 x + 3y = 12 and 3 x - 2y = 5 then

Solve: {:(3x + 5y = 12),(3x - 5y = - 18):}

If 3 x + 4y - 11= 18 and 8x - 6y + 12 = 6 , then what is the value of 5x - 3y - 9 ?

If x : y = 4 :5 , then (3x + y) : (5x + 3y) =