The equilibrium constant for the reaction
`N_(2)(g)+3H_(2)(g)hArrNH_(3)(g)` is K'
K and K' will be related to each other as

The equilibrium constant for the reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) is K and for the reaction (1/2)N_(2)(g)+(3/2)H_(2)(g)hArrNH_(3)(g) is K' K and K' will be related to each other as

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant for the reaction N_2(g) +3H_2(g) harr 2NH_3(g) is K. What will be the equilibrium constant for the reaction involving decompostion of one mol of ammonia?

(K_(c))/(K_(p)) for the reaction, N_(2)(g)+3H_(2)(g)hArr2NH_(3(g)) is

At a constant temperature, the equilibrium constant of the reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) is K and that of the reaction (1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)hArrNH_(3)(g) is sqrt(K) . Explain this difference of K values in spite of the fact that the reactants and products in both the reactions are same.