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The shape of a garden is rectangular in ...

The shape of a garden is rectangular in the middle and semi circular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is `20-(3.5+3.5)` metres].

A

` 129.5, 47`

B

`129.5, 48`

C

`127.7, 49`

D

`189.5, 50`

Text Solution

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The correct Answer is:
To solve the problem of finding the area and perimeter of the garden, which is rectangular in the middle and semi-circular at the ends, we can follow these steps: ### Step 1: Understand the Dimensions The total length of the garden is given as 20 meters. The ends of the garden are semi-circles with a combined diameter of 7 meters (3.5 meters on each side). Therefore, the length of the rectangle can be calculated as: \[ \text{Length of Rectangle} = 20 - (3.5 + 3.5) = 20 - 7 = 13 \text{ meters} \] ### Step 2: Calculate the Area of the Rectangle The area of a rectangle is given by the formula: \[ \text{Area of Rectangle} = \text{Length} \times \text{Breadth} \] Here, the length is 13 meters and the breadth (which is the diameter of the semi-circles) is 7 meters. Thus: \[ \text{Area of Rectangle} = 13 \times 7 = 91 \text{ square meters} \] ### Step 3: Calculate the Area of the Semi-Circles The area of a semi-circle is given by: \[ \text{Area of Semi-Circle} = \frac{1}{2} \pi r^2 \] The radius \( r \) of the semi-circle is half of the diameter: \[ r = \frac{7}{2} = 3.5 \text{ meters} \] Now substituting the value of \( r \): \[ \text{Area of Semi-Circle} = \frac{1}{2} \times \frac{22}{7} \times (3.5)^2 \] Calculating \( (3.5)^2 \): \[ (3.5)^2 = 12.25 \] Now substituting back: \[ \text{Area of Semi-Circle} = \frac{1}{2} \times \frac{22}{7} \times 12.25 \] Calculating this gives: \[ \text{Area of Semi-Circle} = \frac{22 \times 12.25}{14} = \frac{271.5}{14} = 19.25 \text{ square meters} \] Since there are two semi-circles, the total area of the semi-circles is: \[ \text{Total Area of Semi-Circles} = 2 \times 19.25 = 38.5 \text{ square meters} \] ### Step 4: Calculate the Total Area of the Garden Now, adding the area of the rectangle and the total area of the semi-circles: \[ \text{Total Area} = \text{Area of Rectangle} + \text{Total Area of Semi-Circles} \] \[ \text{Total Area} = 91 + 38.5 = 129.5 \text{ square meters} \] ### Step 5: Calculate the Perimeter of the Garden The perimeter of the garden consists of the two lengths of the rectangle and the circumference of the two semi-circles: \[ \text{Perimeter} = 2 \times \text{Length of Rectangle} + \text{Circumference of Semi-Circles} \] The circumference of a full circle is given by: \[ \text{Circumference} = 2 \pi r \] Thus, for a semi-circle: \[ \text{Circumference of Semi-Circle} = \pi r \] Substituting the radius: \[ \text{Circumference of Semi-Circles} = \frac{22}{7} \times 3.5 = 22 \text{ meters} \] Now substituting back into the perimeter formula: \[ \text{Perimeter} = 2 \times 13 + 22 = 26 + 22 = 48 \text{ meters} \] ### Final Results - **Total Area of the Garden:** 129.5 square meters - **Total Perimeter of the Garden:** 48 meters

To solve the problem of finding the area and perimeter of the garden, which is rectangular in the middle and semi-circular at the ends, we can follow these steps: ### Step 1: Understand the Dimensions The total length of the garden is given as 20 meters. The ends of the garden are semi-circles with a combined diameter of 7 meters (3.5 meters on each side). Therefore, the length of the rectangle can be calculated as: \[ \text{Length of Rectangle} = 20 - (3.5 + 3.5) = 20 - 7 = 13 \text{ meters} \] ...
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