দেখাও যে, `int_a^bf(a+b-x)dx=int_a^bf(x)dx`

int_(a)^(b)f(x)dx=int_(b)^(a)f(x)dx .

If f(a+b-x)=f(x),\ then prove that \ int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dx

If f(a+b-x)=f(x),\ then prove that \ int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dx

STATEMENT 1: int_0^pixsinxcos^2xdx=pi/2int_0^pisinxcos^2x dx . STATEMENT 2: int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dx .

STATEMENT 1: int_0^pixsinxcos^2xdx=pi/2int_0^pisinxcos^2x dx . STATEMENT 2: int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dx .

If f(a+b-x)=f(x), then prove that int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dxdot

If f(a+b-x)=f(x), then prove that int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dxdot

If f(a+b-x)=f(x), then prove that int_a^b xf(x)dx =(a+b)/2int_a^bf(x)dxdot

If f(a+b-x)=f(x), then prove that int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dxdot

If f(a+b-x)=f(x), then prove that int_a^b xf(x)dx=(a+b)/2int_a^bf(x)dxdot