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2costheta=x+1/xand 2cos phi=y+1/y then (...

`2costheta=x+1/x`and `2cos phi=y+1/y` then (A)` x^n+1/(x^n)= 2 cos(n theta) n in Z` (B) `x/y+y/x= 2 cos(theta -phi)` (C) `xy+1/(Xy) =2 cos (theta + phi)` (D) `x^my^n +1/(x^my^n)= 2(cos mtheta +n phi), m,n in Z`

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