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Amount of PCl(5) (in moles) need to be a...

Amount of `PCl_(5)` (in moles) need to be added to one litre vessel at `250^(@)C` in order to obtain a concentration of `0.1 "mole"` of `Cl_(2)` for the given change is:
`PCl_(5)hArrPCl_(3)+Cl_(2)` , `K_(c)=0.0414 mol litre^(-1)`

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