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There is a regular hexagon MNOPQR of sid...

There is a regular hexagon MNOPQR of side `5 cm` . aman and ridhima divided it into two different ways . Find the area of this hexagon both ways.

Text Solution

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for ridhima
total area = area 1 + area 2 + area 3
`= 2 xx area 1` + area 2
`= 2 xx 1/2 xx 8 xx 3 + 8 xx 5`
`= 24+40 = 64 cm^2`
for aman
total area = area of 1 + area of 2
= area of `1`
...
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