A particle is subjected to SHM as given by equation `x_1=Asinomegat` and `x_2=A_2sin(omegat+(pi)/(3))`. The maximum acceleration and amplitude of the resultant motion are `a_(max)` and `A`, respectively Then.

A particle is subjected to SHM as given by equations x_1 = A_1 sin omegat and x_2 = A_2 sin (omega t + pi//3) .The maximum acceleration and amplitude of the resultant motion are it a_("max") and A ,respectively , then

A particle is subjected to two SHMs x_(1) = A_(1) sin omegat and x_(2) = A_(2)sin (omegat +(pi)/(4)) . The resultant SHM will have an amplitude of

Two parallel S.H.M.s have equations y_1=A_1sin(omegat+2pi) and y_2=A_2sin(omegat+4pi) . The amplitude of the resultant motion is

Two parallel S.H.M.s have equations y_1=A_1sin(omegat+2pi) and y_2=A_2sin(omega/t+4pi) . The amplitude of the resultant motion is

A particle is subjected to two simple harmonic motions x_(1)=4 sin(100pit) and x_(2)==3 sin ^((100pi t + (pi)/(2)) Then maximum acceleration of the particle is

A particle is subjected to two simple harmonic motions x_1=A_1 sinomegat and x_2=A_2sin(omegat+pi/3) Find the maximum speed of the particle and the maximum acceleration of the particle

x_(1)=A sin (omegat-0.1x) and x_(2)=A sin (omegat-0.1 x-(phi)/2) Resultant amplitude of combined wave is

A particle executes two types of SHM. x_(1) = A_(1) sin omega t " and "x_(2) = A_(2) sin [omega t+(pi)/(3)] , then find the maximum acceleration of the particle.