B.P of `H_(2)O (100^(@)C) `and `H_(2)S( -= 42^(@)C)` is explained by

Calculate the change in enthalpy for the following process at 1 atm H_(2)O(1, 50^(@)C) rarr H_(2)O (g, 150^(@)C) given that Delta H_(v) at 100^(@)C is 40.7 kJ mol^(-1) C_(p)(H_(2)O, l) = 75.0 J mol^(-1)K^(-1) C_(p)(H_(2)O, g) = 33.3 J mol^(-1)K^(-1)

Calculate entropy charge H_(2)O(l,1 atm, 100^(@)C) rarr H_(2)O(g, 1" "atm, 110^(@)) H_(2)O(l, 2" "atm, 100^(@)) rarr H_(2)O(g, 2" "atm, 100^(@)) DeltaH_(vap)=40kJ//"mole" " " C_(p)(l)=75J//"mole"//K " " C_(p)(g)=35 J//"mole"//K

For the reaction H_(2)O_((s)) hArr H_(2)O_((l)) at ""^(@)C and normal pressure

An amount of 3 mole H_(2) O(l) at 100^(@)C and 1 atm is converted into H_(2) O (g) at 100^(@)C and 5 atm. DeltaG for the process is

Which of the followingk is true for the process H_(2) O (s) = H_(2) O (l) at 0^(@)C and 1 atm?