निम्नलिखित फलन का लेखाचित्र खींचिए :
`y={{:(x^(2),"यदि",xlt0),(x,"यदि",0lexle1),(2-x,"यदि",1lexle2):}`.

If f(x)={{:(x",",0lexle1),(x+a",",xgt1):} then

If f(x)={{:(x^(2)" for "0lexle1),(sqrtx" for "1lexle2):}" then "int_(0)^(2)f(x)dx=

Draw the graphs of the following : y = {{:(x^(2) , if , x lt 0),(x , if, 0lexle1 ),((1)/(x),if,xgt1):}

Value of 'c' of Rolle's theorem for f(x) = {:{ (x^(2) + 1,"when "0lexle1),(3 - x,"when "1lexle2):}

Graph the following piece wise-defined function : {{:(-x",",xlt0),(x^(2)",",0lexle1),(1",",xgt1):}

f(x)={(ae^x+be^(-x),-1lexle1),(cx^2,1lexle3),(2ax+c,3lexle4):} , f'(0)+f'(2)=

Evaluate int_(0)^(3)f(x)dx , where f(x)={:{(x+3,0lexle2),(3x" ",2lexle3):}

Evaluate int_0^3 f(x)dx , Where f(x)={(x,+,3,,,0lexle2),(3x,,,,,2lexle3):}

Discuss the continuity of the function f, where f is defined by : f(x)={{:(2x", if "xlt0),(0", if "0lexle1),(4x", if "xgt1):}