Three cells of emf 2.0 v, 1.8 V and 1.5 V are connected in series. Their internal resistances are `0.05 Omega, 0.7 Omega " and " 1 Omega` respectively. If the battery is connected to an external resistor of `4 Omega` via a very resistance ammeter, what would be the reading in the ammeter ?

(a) Three cells of emfs, 1.5 V, 2.0V and 2.5 V are connected in series. Their internal resistance are 0.20 Omega, 0.15 Omega and 0.15 Omega respectively. The battery is connected to an external resistor of 5.5 Omega via a very low resistance ammeter, what would be the reading of ammeter? (b) If the three cells above were joined in parallel, would they be characterised by a definite emf and internal resistance (independent of their individual internal resistance )? If not, how will you obtain currents in different branches of the circuit ?

A battery is formed by connecting three cells in series . The emfs of cells are 5 V, 2.5 V and 1.5 V and their internal resistance are 0.5 Omega ,0.05 Omega and 0.45 Omega respectively. This battery is connected across a load resistance of 5 Omega what current will be supplied by the battery ? if the cell of emf 1.5 V were connected with reverse polarity then what would have been the current supplied by the battery ?

Three identical cells of emf 2 V and internal resistances 0.20 Omega are connected in series. The combination is further connected to an external resistor of 6 Omega . Calculate the current through 6 Omega resistor.

A cell of e.m.f. 1.8 V and internal resistance 2 Omega is connected in series with an ammeter of resistance 0.7 Omega and a resistor of 4.5 Omega as shown in Fig. What would be the reading of the ammeter ?

A cell of e.m.f. 2V and internal resistance 1.2. Omega is connected with an ammeter of resistance 0.8 Omega and two resistors of 4.5 Omega and 9 Omega as shown in the diagram below: What would be the reading on the Ammeter?

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected IF the reading of the ammter is 0.02 A.what is the resistance of the voltmeter?

Two cells one of emf 1.4 V and internal resistance 0.6 Omega the other of emf 2.5. V and internal resistance 0.3 Omega are connected in parallel and the combination is connected in series with an external resistance of 4 Omega . What is the current through this resistance?