int(0)^(1)(log(e)(1+x))/(1+x^(2))dx=(pi)...

int_(0)^(1)(log_(e)(1+x))/(1+x^(2))dx=(pi)/(8)log_(e)2

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int_(0)^(1)(log|1+x|)/(1+x^(2))dx=(pi)/(8)log2

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int(log_(e)x)/((1+x)^(2))dx

int(log_(e)x)/((1+x)^(2))dx

int_(1)^(x)log_(e)[x]dx

" (2) "int_(1)^(2)(log e^(x))/(x^(2))dx

int_(0)^(log 2)(e^(x))/(1+e^(x))dx=

int_(0)^(log 2)(e^(x))/(1+e^(x))dx=

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Show that int_(0)^(1)tan ^(-1)x+tan^(-1)(1-x)dx=(pi)/(2)-log_(e)2

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