" 9."(root(3)(x)-root(3)(y))^(6)

Using binomial theorem, expand each of the following: (root(3)(x)-root(3)(y))^(6)

If root(3)(3(root(3)(x)-(1)/(root(3)(x)))) =2,then root(3)(x)-(1)/(root(3)(x))

If root(3)(3(root(3)(x)-(1)/(root(3)(x))))=2, then root(3)(x)-(1)/(root(3)(x))

Rationalize the denominator. (3 root(3)(5))/(root(3)(9))

root(3)(7)times root(6)(6)

(a) (root(4)(9)+root(4)(4))^(1/3)*(root(4)(9)-root(4)(4))^(1/3) simplify

Simplify [root(3)(root(6)(2^(9)))]^(4)xx[root(6)(root(3)(2^(9)))]^(4) .

Simplify: [root(3)(root(6)(5^(9)))]^(8)[root(6)(root(3)(5^(9)))]^(8)

(2)/(root(3)(9) - root(3)(3)+1) - (1)/(root(3)(9)+root(3)(3)+1) = 1) 1 , 2) -1 , 3) root(3)(3) , 4) - root(3)(3)