A metal ball cools from `62^(@)C` to `50^(@)C` in `10min` and to `42^(@)C` the next ten minutes. What will be its temperature at the end of next ten minutes ?

A copper ball cools from 62^(@) C , C to 50^(@) C in 10 minutes and to 42^(@) C ill the next 1 Ominutes. Calculate its temperature at the end of allother 10 minutes.

A body cools from 62^(@)C to 50^(@)C in 10 minutes and to 42^(@)C in the next 10 minutes. Find the temperature of surroundings.

A metal ball cools from 64^(@)C to 50^(@)C in 10 minutes and to 42^(@)C in the next 10 minutes. The ratio of the rates of fall of temperature during the two intervals is

A metal ball cools from 64^(@)C to 50^(@)C in 10 minutes and to 42^(@)C in the next 10 minutes. The ratio of the rates of fall of temperature during the two intervals is

A metal bal cools from 64^(@)C to 50^(@)C in 10 minutes and to 42^(@)C in next 10 minutes. The ratio of rates of fall of temperature during the two internal is

A body cools from 40^@C to 30^@C in 5 minutes and to 26^@C in next 3 minutes. What will be the temperature of surroundings?

A body cools from 50^(@)C to 46^(@)C in 5 minutes and to 40^(@)C in the next 10 minutes. The surrounding temperature is :