Find the magnitude and direction to the velocity of an object at any instant during the oblique projection of projectile.

Assertion: In projectile motion, the acceleration is constant in both magnitude and direction but the velocity changes in both magnitude and direction. Reason: When a force or accelration is acting in an oblique direction to the direction of velocity then both magnitude and direction of the velocity may be changed.

Assertion: In projectile motion, the acceleration is constant in both magnitude and direction but the velocity changes in both magnitude and direction. Reason: When a force or accelration is acting in an oblique direction to the direction of velocity then both magnitude and direction of the velocity may be changed.

Assertion: In projectile motion, the acceleration is constant in both magnitude and direction but the velocity changes in both magnitude and direction. Reason: When a force or accelration is acting in an oblique direction to the direction of velocity then both magnitude and direction of the velocity may be changed.

When a particle is projected at some angle with the horizontal, the path of the particle is parabolic. In the process the horizontal velocity remains constant but the magnitude of vertical velocity changes. At any instant during flight the acceleration of the particle remains g in vertically downward direction. During flight at any point the path of particle can be considered as a part of circle and radius of that circle is called the radius of curvature of the path Consider that a particle is projected with velocity u=10 m//s at an angle theta=60^(@) with the horizontal and take value of g=10m//s^(2) . Now answer the following questions. The magnitude of acceleration of particle at that instant is

When a particle is projected at some angle with the horizontal, the path of the particle is parabolic. In the process the horizontal velocity remains constant but the magnitude of vertical velocity changes. At any instant during flight the acceleration of the particle remains g in vertically downward direction. During flight at any point the path of particle can be considered as a part of circle and radius of that circle is called the radius of curvature of the path Consider that a particle is projected with velocity u=10 m//s at an angle theta=60^(@) with the horizontal and take value of g=10m//s^(2) . Now answer the following questions. The radius of curvature of path of particle at the instant when the velocity vector of the particle becomes perpendicular to initial velocity vector is

When a particle is projected at some angle with the horizontal, the path of the particle is parabolic. In the process the horizontal velocity remains constant but the magnitude of vertical velocity changes. At any instant during flight the acceleration of the particle remains g in vertically downward direction. During flight at any point the path of particle can be considered as a part of circle and radius of that circle is called the radius of curvature of the path Consider that a particle is projected with velocity u=10 m//s at an angle theta=60^(@) with the horizontal and take value of g=10m//s^(2) . Now answer the following questions. Tangential acceleration of particle at that instant is

In oblique projection time of flight of a projectile is

A particle is projected with an initial velocity u, making an angle theta with the horizontal. Find the equation of the trajectory of the particle at any instant after the projection. Find expressions for the maximum height gained by the particle and its horizontal range.