A particle aimed at a target projected with an angle `15^(@)` with the horizontal is short of the target by 10m .If projected with an angle of `45^(@)` is away from the target by 15m then the angle of projection to hit the target is

A particle aimed at a target, projected with an angle 15^(0) with the horizontal is short of the target by 10 m. If projected with an angle of 45° is away from the target by 15 m, then the angle of projection to hit the target is

A particle is thrown at an angle of 15^(@) with the horizontal and the range is 1.5 km. What is the range when it is projected at 45^(@) ?

A bullet is fired at an angle of 15^(@) with the horizontal and it hits the ground 3 km away. Can we hit a target at a distance of 7 km by just adjusting its angle of projection ?

A bullet is fired at an angle of 15^(@) with the horizontal and it hits the ground 3 km away. Can we hit a target at a distance of 7 km by just adjusting its angle of projection ?

A bullet fired at an angle of 30^(@) with the horizontal hits the ground 3 sqrt 3 km away. Can wr hit a target at a distance of 6 sqrt 2km by adjustion its angle of projection?

A bullet is fired at an angle of 15^@ with the horizontal and hits the ground 6 km away. Is it possible to hit a target 10 km away by adjusting the angle of projection assuming the initial speed to be the same ?

A projectile is aimed at a mark on the horizontal plane through the point of projection and falls 12 m short when the angle of projection is 15^(@) , white it overshoots the mark by 24 m when the angle of projection is 45^(@) . Find the angle of projection to hit the mark.