A voltmeter reads the potential difference across the terminals of an old battery as `1.40 V`, while a potentiometer reads its voltage to be `1.55 V`. The voltmeter resistance is `280 Omega`.

A battery of emf 1.4 V and internal resistance 2 Omega is connected to a resistor of 100 omega resistance through an ammeter. This resistance of the ammeter is 4//3 Omega . A voltmeter has also been connected to find the potential difference across the resistor. a. Draw the circuit diagram. b. The ammeter reads 0.02 A . What is the resistance of the voltmeter? c. The voltmeter reads 1.1 V . What is the error in the reading?

A battery of emf 1.4 V and internal resistance 2 Omega is connected to a resistor of 100 omega resistance through an ammeter. This resistance of the ammeter is 4//3 Omega . A voltmeter has also been connected to find the potential difference across the resistor. a. Draw the circuit diagram. b. The ammeter reads 0.02 A . What is the resistance of the voltmeter? c. The voltmeter reads 1.1 V . What is the error in the reading?

In the experiment of calibration of voltmeter, a standard cell of emf 1.1 V is balanced against 440 cm of potentiometer wire. The potentail difference across the ends of a resistance is found to balance aginst 220 cm of the wire. The corresponding reading of the voltmeter is 0.5 V . Find theerror in the reading of voltmeter.

A high resistance voltmeter measures the potential difference across a battery to be 9-0 V. On connecting a 24 2 resistor across the terminals of the battery, the voltmeter reads 7.2 V. Calculate the internal resistance of the battery.

A voltmeter of resistance R is to be used to measure the potential difference across a resistance r . The nearest reading in the absence of voltmeter ?

The voltmeter reads 40 V across 60 Omega resistance. The resistance of voltmeter is. .

A 100V battery has an internal resistance 3 Omega . What is the reading of a voltmeter having resistance 200 Omega , when placed across the terminals of the battery? What should be the minimum value of the voltmeter resistance so that the error in finding the emf of the battery may not be more than 1%?