Reduce the lines `3x-4y+4=0` and `4x-3y+12=0` to the normal form and hence determine which line is nearer to the origin.

Reduce the lines 3x - 4y + 4 = 0 and 4x - 3y + 12 = 0 to the normal form and hence find which line is nearer to the origin.

Reduce the lines 3x-4y+4=0 and 2x+4y-5=0 to the normal form and hence find which line is nearer to the origin.

Reduce the lines 3x-4y+4=0\ a n d\ 2x+4y-5=0 to the normal form and hence find which line is nearer to the origin.

Reduce the equation of the straight line 3x+4y+15=0 to normal form and find the perpendicular distance of the line from the origin.

Which of the two 3x-4y+4=0 and 3x-3y+12=0 is nearer to origin

The normal form of line sqrt(3)x=y+4=0 is

Which of the st.lines 2x-y+3=0 and x-4y-7=0 is farther from the origin ?

Which of the st.lines 2x-y+3=0 and x-4y-7=0 is farther from the origin ?

Which of the st. lines 2x - y + 3 = 0 and x- 4y-7=0 is farther from the origin ?

Reduce the equation 3x-4y+12=0 to intercepts form. Hence, find the length of the portion of the line intercepted between the axes.