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" For the reaction: "Cu((s))+2Ag((aq))^(...

" For the reaction: "Cu_((s))+2Ag_((aq))^(+)rightleftharpoons Cu_((aq))^(+2)+2Ag_((s))" the equilibrium constant is given by "

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For the reaction: Cu(s) + 2Ag_((aq))^+ Leftrightarrow Cu_((aq))^(2+) +2Ag_((s)) , the equilibrium constant is given by

In a cell reaction, Cu_((s))+ 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_((s)) E_"cell"^@ =+0.46 V . If the concentration of Cu^(2+) ions is doubled then E_"cell"^@ will be

In a cell reaction, Cu_((s))+ 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_((s)) E_"cell"^@ =+0.46 V . If the concentration of Cu^(2+) ions is doubled then E_"cell"^@ will be

The equilibrium constant of the reaction Cu_((s)) + 2Ag_((aq))^(+) iff Cu_((aq))^(+2) + 2Ag_((s)) , " is " x xx 10^(15) , 'x' is ( E^(@) = 0.46 V at 298 K )