Point P is (-2,-3) and point Q is (3,7) . The point A on the axis for which PA+AQ is least is (-,0) . Then A =

P(3, 4), Q(-7, 6). The point A on x-axis for which PA +AQ is least is: 1) (-2, 0) , 2) (-1, 0) , 3) (3,0) , 4) (2,0)

If P-=(-2, -3) and Q-= (3, 7) , then point A on the X- axis such that AP^(2)+AQ^(2) is minimum is

The point P is (-2,5). Find the point A on the X axis and the point B on the Y-axis such that the slope of the line AP is 3 and slop of line BP is 7.

Is P(7,0) and Q (0,7) represent the same point ?

If (p,q) is a point on x-axis,which is equidistant from (1,2) and (2,3). Find p and q:

Suppose P(-2,3) and Q(3,7) are two points such that PA^(2)+QA^(2) is the least . Then the point A on the x-axis is

A man starts from the point P(−3,4) and reaches at point Q(0,1) touches x-axis at point R such that PR+RQ is least then position of point R is (a) (3/5,0) (b) (-3/5,0) (c) (-2/5,0) (d) (-2,0)

A(2,0), B(-2, 0) are two points. The locus of the point P which moves such that PA-PB=2 is

A point P lies on the x-axis and another point Q lies on the y-axis. Write the abscissa of point Q.

A point P lies on x-axis and another point Q lies on y-axis. Write the abscissa of the point Q.